You should not have the same variable name for 2 seperate things. 1 variable is the
filename, 2 variable is the File Descriptor.
$file = "C:\\inetpub\\wwwroot\\packtracker\\LSE\\".$cr.".txt";
$fd = fopen($file, 'w');
--
Gerardo S. Rojas
mailto:[EMAIL PROTECTED]
-Original Message-
Fr
Thanks for the pointers guys.
The revised code (it works) is:
$fp2 = "C:\\inetpub\\wwwroot\\packtracker\\LSE\\".$cr.".txt";
if (!$fp2 = fopen($fp2, 'w')) {
print "Cannot open the bloody file ($fp2)";
exit;
}
if (!fwrite($fp2, $content)) {
print "Cannot write to file ($fp2)";
exit;
You have these two lines
$fp2 = "C:\\inetpub\\wwwroot\packtracker\\LSE\\".$cr.".txt";
$fp3 = "C:\\inetpub\\wwwroot\packtracker\\LSE\\".$cr.".doc";
Why do you have double slashes on every place but one ? :-)
Luis
- Original Message -
From: "George Pitcher" <[EMAIL PROTECTED]>
To: <[EMAIL
Save all programers! (sorry my "brazilian english")
I have a simple doubt, but i´m tired because i not found answers...
Why, inside a class, declarare $this variables in a format "var $varname;"
before of a constructor?
And, please, what intend the "&" signal before functions name?
I know the ar
George,
In the following line you open file $fp...
if (!$fp = fopen($fp2, 'w')) {
but then you try to write to file handle $fp2...
if (!fwrite($fp2, $content)) {
The file name is stored in $fp2 but you've named the handle as $fp. Change
the $fp2 to $fp in the above line that might fix it. Mayb
php-windows Digest 9 Sep 2003 14:38:28 - Issue 1903
Topics (messages 21329 through 21332):
Re: PDF and FDF
21329 by: Cesar Cordovez
Need to call VB from PHP script. Is this hard to do?
21330 by: karen97214.yahoo.com
21331 by: Sek-Mun Wong
Problem writing to a file
Hi all,
I'm having a problem writing to a text file.
This is the error message:
= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =
Warning: fwrite():
supplied argument is not a valid stream resource in
C:\Inetpub\wwwroot\packtracker\lse\pub_req_start2.php on line 276
Cannot write
