ok well since my page works great on my hosting server which uses Linux i'm
just gonna install linux. My version of Windows just doesn't support it.
"Joey" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> yes i've tried that too *sigh* :( i've read the manual o
php-windows Digest 20 Apr 2002 03:33:26 - Issue 1102
Topics (messages 13190 through 13204):
A Breath fo Fresh Air -- Bandwidth Waster
13190 by: R.S. Herhuth
mysql_fetch_array()
13191 by: Guilherme Dávalos
Creating dynamic variables and assigning values in a while statement
yes i've tried that too *sigh* :( i've read the manual over and over again
and installed it a few times and added all those lines ppl suggested but
still no luck. I'm about to just give up. I know how to work PHP but I just
can't find where this problem comes from. Maybe it's a windows thingy who
Hi, I am a newbie in php. I have to upload an Image to a BLOB field in Mysql. But when
I insert the field it save the path of the image file and not the image itself.
This is the code:
Upload.php
Kompatscher & Cia Ltda
";
echo "";
echo "";
echo "Código";
echo "";
echo "";
$i=$linha['
I believe that I am close to getting this to work but now I am getting the
following error when trying to view .php files in my browser:
Warning: Failed opening '/wwwroot/[directory]/time.php' for inclusion
(include_path='c:\php4\pear') in Unknown on line 0,
where [directory] is the directory of m
I'm working with a company doing internet intrusion detection and there is an exploit
known in PHP that I am trying to detect.
See http://www.securiteam.com/windowsntfocus/5ZP030U60U.html for details about it.
Basically if someone does something like
"http://www.example.com/php/php.exe?d:\winnt
Here is your problem:
below is your code:
$result = mssql_query($query,$link); file://JUST CRASHES ON THIS LINE
$r = mssql_rows_affected ( $link);
The 2nd line there:
$r = mssql_rows_affected( $link );
should be
$r = mssql_rows_affected( $result );
AND, you do not need to pass t
Here is your problem:
below is your code:
$result = mssql_query($query,$link); file://JUST CRASHES ON THIS LINE
$r = mssql_rows_affected ( $link);
The 2nd line there:
$r = mssql_rows_affected( $link );
should be
$r = mssql_rows_affected( $result );
AND, you do not need to pass t
Ooops, I'm sure you've figured this one out by now ... 3+ months later.
--
Nicole Amashta
Web Application Developer
www.aeontrek.com
"Dion" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I am running Apache 1.3 on WindowsXP just for some developement stuff
>>> $counter = "0";
This line may work in your code, but if you are assigning numbers, you don't
need to put quotes around them since they are numbers and not strings.
If you then want to use that number as part of a string, do like you did:
$temp="ydata$counter";
or do like so:
$temp
Keep reading the documentation ... if that's the only line you added, you
aren't done.
--
Nicole Amashta
Web Application Developer
www.aeontrek.com
"Joey" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Ok i'm using Apache 1.3.24 and PHP 4.1.2 and the windows
Did you read your documentation on setting up Apache and PHP with Apache?
You have several files to configure in order to get PHP working with Apache
and vice versa
When in doubt, RTFM :)
http://www.php.net
http://www.apache.org
If you need further help, let me know.
--
Nicole Amashta
We
Joey,
It sounds like PHP is not telling apache that is a Content-type of
text/html. See this line in PHP.ini (which should be in c:\).
default_mimetype = "text/html"
Also, try adding a line in your httpd.conf for .html files like this:
AddType application/x-httpd-php .html
and then see if
Ok i'm using Apache 1.3.24 and PHP 4.1.2 and the windows platform is XP home
edition
yes i've added this line in my httpd.conf file
AddType application/x-httpd-php .php
"Joey" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Everytime i try to view a php file o
Good morning everyone,
Kinda got stuck here. Must be brain dead this morning. I'm trying to
loop thru a results set from a mysql query that will always return an
array of 13 results. I need to loop thru using a while statement and
create dynamic variables $temp1 - $temp13 and $tempcolor1 - $tempc
Hi folks,
I'm trying to run an application, made on PHP3/LINUX, on PHP 4.1.2/Windows in module
scheme. But its seems be reclaiming that mysql_fetch_array() function doesn't work at
4.1.2 version. How can i fix it?
[ ]'s
Pajé
I just want to say that after two weeks of working with PHP I'm finally
getting it (thanks to this list and it's contributors!). PHP rocks!
Ron
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php-windows Digest 19 Apr 2002 11:43:30 - Issue 1101
Topics (messages 13183 through 13189):
can't view php
13183 by: joey
13184 by: Steff
Re: Connecting to a remote database
13185 by: Steff
Re: Apache 2.0.35 & php 4.2.0 RC4 includes
13186 by: Steff
fastcgi
It does not work. Can somebody to help me!?!?!?
Each time I try to write with ming it does not work. I have Popup: The
instruction At "0x00b907fc" referenced memory At "0x00abc000". The memory
could not Be "written".
I maked a file .mdb by my self (if the file would not be portable...) I
u
here are the gifs...
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Hi php dev,
First, sorry for my bad english!
Second, i'm using PHP with IIS (ISAPI & CGI) for months on production
servers
and all work fine :-)
Third, i'm trying to parse php files via fastcgi, but i have the "server
error" message
you can find in the gif files the settings for the registry an
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