To: [EMAIL PROTECTED]
Subject: [PHP-INST] Image functions
Hello,
I have the following code:
$return_val = ( ($img = ImageCreateFromJPEG ( $image_file_path )) &&
$return_val == 1 ) ? "1" : "0";
but I become the following error message:
Fatal error: Call to undefined fun
Hello,
I have the following code:
$return_val = ( ($img = ImageCreateFromJPEG ( $image_file_path )) &&
$return_val == 1 ) ? "1" : "0";
but I become the following error message:
Fatal error: Call to undefined function: imagecreatefromjpeg() in C:\Program
Files\Apache Group\Apache2\htdocs\res
