are you pass the two functions you return link from mysql_connect() or
mysql_pconnect() ??
jim
- Original Message -
From: "sc" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, October 30, 2001 6:15 PM
Subject: Re: [PHP] php & mysql prob...
>
= mysql_error($dblink);
> $errno = mysql_errno($dblink);
> or
> echo mysql_error($dblink);
> echo mysql_errno($dblink);
>
> jim
> - Original Message -
> From: "sc" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Tuesday, October 30, 2001 6:01
October 30, 2001 6:01 PM
Subject: Re: [PHP] php & mysql prob...
> ok i thought it would be working, but on testing it more it still isn't
> going for me i took off the ' ' from the table name and its still
coming
> up with an error on line 17 with the same
ok i thought it would be working, but on testing it more it still isn't
going for me i took off the ' ' from the table name and its still coming
up with an error on line 17 with the same error message... the mysql_error()
isn't echoing anything that has gone wrong.. (did before)..
Any ideas?
On Wed, 31 Oct 2001 11:47, Jason Brooke wrote:
> Or the single quotes around the table name in the sql string
>
> > Your query is probably broken - do some error checking after your
> > database call with mysql_error() and see what the problem is.
> >
> > Guess; the table name.
That's what I mean
Yeah sorry about that, didn't mean to send out 3...
Ok i got it working... thanks for all the replys...
-sc
"David Robley" <[EMAIL PROTECTED]> wrote in message
01103111392904.28397@www">news:01103111392904.28397@www...
> On Wed, 31 Oct 2001 11:25, sc wrote:
> > Hi;
> >
> > i keep getting an er
Or the single quotes around the table name in the sql string
> Your query is probably broken - do some error checking after your
> database call with mysql_error() and see what the problem is.
>
> Guess; the table name.
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On Wed, 31 Oct 2001 11:25, sc wrote:
> Hi;
>
> i keep getting an error of: Warning: Supplied argument is not a valid
> MySQL result resource in /datascripts/insertdata.php on line 17...
>
> Line 17 is: $row = mysql_fetch_assoc($test);
>
> and here is the rest of it (not all of it though):
>
> for
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