Welcome Nicolas,
=You didn't actually say what the problem was!
=Some have made suggestions, please also consider (below):
i'm new and i'm trouble with this code :'( can U help me please ??
this is the code :
while ($cd_tbl = mysql_fetch_array ($result))
{
$cd_id = $cd_tbl['cd_id'];
$cd_oeuvre
> echo "$cd_id";
Strings work differently when the outer quotes are double or single quotes.
Inside double quotes variables will be converted into their values. Inside
single they will not.
So:
$var = 'Hello World';
echo "$var\n";
will result in
Hello World
and:
$var = 'Hello World';
echo '$va
ðÒÉ×ÅÔ!
Nicolas GUILLOU wrote:
You may either write:
> echo "$cd_id";
or
> echo "size=1>$cd_compositeur";
ðÏËÁ
áÌØÂÅÒÔÏ
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LoRd, CaN yOu HeAr Me, LiKe I'm HeArInG yOu?
lOrD i'M sHiNiNg...
YoU kNoW I AlMoSt LoSt My MiNd, BuT
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