Oops ... That's not balanced. Add another ) at the end of the if.
/bsh/
Billy S Halsey wrote:
> Try an extra layer of parens:
>
> if (($fp = fopen("http://www.anyurl.com";, "r") == NULL)
> {
> echo "not valid";
> }
> else
> {
> echo "this is a valid url";
> }
>
>
> Roberts, Mark wrote
Try an extra layer of parens:
if (($fp = fopen("http://www.anyurl.com";, "r") == NULL)
{
echo "not valid";
}
else
{
echo "this is a valid url";
}
Roberts, Mark wrote:
> I am using the following to verify a url:
>
> if (!$fp = fopen("http://www.anyurl.com";, "r"))
> {
> ec
Hi Dmitry,
In case you want a regular expression to check if it is a valid url you can try this...
$url = "yoururl";
if(empty($url) && !eregi("^http://[A-Za-z0-9\%\?\_\:\~\/\.-]+$,$url))
$errmsg="$url doesn't look like a valid URL\n";
I hope this helps.
Subodh Gupta
I have learned, Joy i
well, you can try fsockopen.
see it on php.net/fsockopen
it will even return you an error if not connected.
start from the example describing the function on PHP.net/fsockopen (did I
misspelled it?)
Sincerely,
Maxim Maletsky
Founder, Chief Developer
PHPBeginner.com (Where PHP Begins)
[E
How do you mean, "check"? Do you want to use a regular expression to see if
it's a valid URL, or do you want to open a connection to it and see if the
site actually exists?
--
Plutarck
Should be working on something...
...but forgot what it was.
"Dmitry" <[EMAIL PROTECTED]> wrote in message
[E
5 matches
Mail list logo
