The following code was taken directly from
www.php.net/date
$dob_month || ($dob_month==$cur_month &&
$cur_day>=$dob_day) )
return $cur_year-$dob_year;
else
return $cur_year-$dob_year-1;
}
?>
Mark Cain`
- Original Message -
From: "Ryan A" <[EMAIL PROTECTE
On Tuesday 03 May 2005 22:41, Ryan A wrote:
> Hey,
> Anybody have an age function where i can pass a date object and get back an
> int?
>
> eg:
> $years_old=get_years("1979-12-07");
Use time and mktime.
$birthday = ""1979-12-07";
$birdthday_time = mktime(0, 0, 0, substr($birthday, 5, 2), substr
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