On Jul 7, 2005, at 10:17 PM, Bruno B B Magalhães wrote:
Hi Edward,
thanks for replying!
[snip]
Why 1976, because it's a leap year and is between valid range for
windows systems.
Let me try to explain the rest.
First I get the input year... which by the way is working fine here...
preg_
Just a quick fix, as now I've tested in a real environment, with a
real application, and now it's working 100%, well, I think so.
/
*
* Stritotime workaround for dates before 1970 and after 2038
***
Hi Edward,
thanks for replying!
On Jul 7, 2005, at 10:44 PM, Edward Vermillion wrote:
One problem is that there's no accounting for leap years, but I
don't know if that's gonna cause you any problems or not.
Course it have, when we multiply the year offset by 31557376.189582
we are using t
On Jul 7, 2005, at 7:54 PM, Bruno B B Magalhães wrote:
Hi Folks,
Well I think I got it, at least it's working more or less to me now...
I really would appreciate any comments or suggestions.
function str2time($input = '12/31/1969')
{
if(($output = strtotime($input)) !== -1)
Hi Folks,
Well I think I got it, at least it's working more or less to me now...
I really would appreciate any comments or suggestions.
function str2time($input = '12/31/1969')
{
if(($output = strtotime($input)) !== -1)
{
return $output;
}
else
Hi Richard,
Well, I took a look at, and I think it is TOO complex to handler a
simple thing..
Well, that's my little contribution:
function str2time($input = '12/31/1969')
{
$year= substr($input, -4);
$input= substr_replace($input, 1976 , -4);
return
Hello Bruno,
Thursday, July 7, 2005, 7:04:44 PM, you wrote:
BBBM> I've read the manual, and the ADOdb Date package functions, and
BBBM> I am not using this because I want to keep my framework simple,
BBBM> flexible, and fast.
BBBM> Well, I just want a simple way to translate dates (I know what
B
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