On Tuesday 08 June 2004 19:13, php-general wrote:
> $var3 is defined as
>
> $var3 = "$var1$var2";
>
> in the body of the if ($button1) statement !?
what is button1 supposed to do and what is button2 supposed to do?
--
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Sy
On Tuesday 08 June 2004 18:50, php-general wrote:
> Only pressing the "Display concatenated strings"-button should output the
> concatenated string, but this does not work, and I do not understand why.
$var3 is not defined.
--
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source S
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