Re: [PHP] Re: Javascript Mouseover Help

2004-03-18 Thread Five
> F> F> $table_1 = "".$name.""; > F> $table_2 = "".$message.""; > > F> $name = "blah blah"; > > F> if(blah blah){ > F> echo $table_1;} > F> else{ > F> echo $table_2;} > ?>> > > You have to define variable $name before you try to use it. > The only other way would be to eval the string but

Re: [PHP] Re: Javascript Mouseover Help

2004-03-18 Thread Tom Rogers
Hi, Friday, March 19, 2004, 12:44:40 AM, you wrote: F> I would be very interested in a solution to this problem because I have a similar one. F> I stored tables on a page. F> examp: F> $table_1 = "".$name.""; F> $table_2 = "".$message.""; F> etc... F> and included the page and used the variab