On Saturday 10 August 2002 01:50, Gandalf wrote:
> Well of course $foo[0] contains the first dimension of the $foo array and
> the same goes for $bar[0].
The first rule of debugging is not to assume anything.
Perhaps I should've phrased my question better:
"Print out the damn things and see wh
On Fri, Aug 09, 2002 at 07:50:46PM +0200, Gandalf wrote:
> Well of course $foo[0] contains the first dimension of the $foo array and
> the same goes for $bar[0].
>
> It is still not working as it should, i am close to going nuts.
If I understood you correctly, there is no element 0 in $foo and
Well of course $foo[0] contains the first dimension of the $foo array and
the same goes for $bar[0].
It is still not working as it should, i am close to going nuts.
At 11:43 09.08.2002 +0800, you wrote:
>On Friday 09 August 2002 06:14, Gandalf wrote:
>
> >
> > $diff = array_diff($foo[0], $bar[0
On Friday 09 August 2002 06:14, Gandalf wrote:
>
> $diff = array_diff($foo[0], $bar[0]);
What does $foo[0] and $bar[0] contain?
--
Jason Wong -> Gremlins Associates -> www.gremlins.com.hk
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