on 24/02/03 11:42 AM, Jason Lange ([EMAIL PROTECTED]) wrote:
> What you might try is removing the single-quotes from around PHP_SELF.
>
> Before: $_SERVER['PHP_SELF']
> After: $_SERVER[PHP_SELF]
>
> Another note: as far as I can tell you do not need the braces ({}) to
> enclose a variable withi
At 01:42 24.02.2003, Jason Lange spoke out and said:
[snip]
>What you might try is removing the single-quotes from around PHP_SELF.
>
>Before: $_SERVER['PHP_SELF']
>After: $_SERVER[PHP_SELF]
This is only valid if the array is contained within a double quote
> What you might try is removing the single-quotes from around PHP_SELF.
>
> Before: $_SERVER['PHP_SELF']
> After: $_SERVER[PHP_SELF]
>
> Another note: as far as I can tell you do not need the braces ({}) to
> enclose a variable within a double-quoted string. I may be wrong, but
> nothing I've rea
What you might try is removing the single-quotes from around PHP_SELF.
Before: $_SERVER['PHP_SELF']
After: $_SERVER[PHP_SELF]
Another note: as far as I can tell you do not need the braces ({}) to
enclose a variable within a double-quoted string. I may be wrong, but
nothing I've read advocates d
On Sun, 23 Feb 2003 18:55:06 -0500, you wrote:
>Could someone tell me why this code prompts a parse error. I have tried it
>several different way. The statement is called from within a function:
>
>print "action=\"$_SERVER['PHP_SELF']\">\n";
echo ('' . "\n");
works for me (moved the variable out
At 00:55 24.02.2003, Peter Gumbrell said:
[snip]
>Could someone tell me why this code prompts a parse error. I have tried it
>several different way. The statement is called from within a function:
>
>print "action=\"$_SERVER['PHP_SELF']\">\n";
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