"long huynh" <[EMAIL PROTECTED]> wrote:
> I think the function should be mysql_num_rows. There's an mSQL function
> msql_numrows, but for MySQL it needs the second underscore in between
'num'
> and 'rows'.
>
> > $num = mysql_numrows($result);
Either will work. mysql_numrows() is the old name of
I think the function should be mysql_num_rows. There's an mSQL function
msql_numrows, but for MySQL it needs the second underscore in between 'num'
and 'rows'.
> $num = mysql_numrows($result);
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> "Jeff Oien" <[EMAIL PROTECTED]> wrote:
> > This code won't work. I'm trying to get an error if the username
> > is entered incorrectly but it won't go through the if brackets. I even
> > tried printing out $num and it's 0. I also tried
> > if ($num = "0") {
> > if ($num = '0') {
>
> The single
At 11:51 AM 4/6/01 -0500, Jeff Oien wrote:
>if ($num = 0) {
> print "error message etc.
> exit;
>}
This "conditional" will always run. you are assigning $num the value of
zero within your if() statement, and that assignation actually happens, so
the result is "true" and the
The comparison operator is ==. = means "assign". Try:
if ($num == 0) {
foo(bar, baz);
}
AFAIK what your code means is "assign 0 to $num and then, if that worked,
print the error message."
HTH
Jon
-Original Message-
From: Jeff Oien [mailto:[EMAIL PROTECTED]]
Sent: 06 April 2001
"Jeff Oien" <[EMAIL PROTECTED]> wrote:
> This code won't work. I'm trying to get an error if the username
> is entered incorrectly but it won't go through the if brackets. I even
> tried printing out $num and it's 0. I also tried
> if ($num = "0") {
> if ($num = '0') {
The single "=" sets the var
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