Try naming the file with a .php extension. It is also possible your server
does not support php.
Good luck,
Chris
From: "Jonathan" <[EMAIL PROTECTED]>
Reply-To: "Jonathan" <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Subject: [PHP] new to php, need help..
Date: Thu, 20 Feb 2003 01:34:12 -0600
hi a
Firstly, cross-posting like this is a huge
no-no, please don't do that again.
> When the script runs it displays Array.
Printing arrays directly will do that. Logically
speaking, how do you expect PHP to know what
value to get here? You are SELECTing many.
> I am running WIN2K and IIS 5
Hello,
The result $Location_info is an array.So you've got the answer 'Array'.
Consider that you requested MySQL to fetch several columns through SQL
"Select * from...". So the result was an array.
You can get the content of the result like $Location_info[0],$Location_
info[2],and so on.
Hir
change:
$Location_Info = mysql_fetch_row($result);
to:
$row = mysql_fetch_array($result);
$Location_Info = $row['fieldname'];
replace "fieldname" with the real name of your database field
-Original Message-
From: Jason Tobias [mailto:[EMAIL PROTECTED]]
Sent: Thursday, April 04, 2002 9:2
Michele,
Possible a dumb question, but does the machine you are running it on have PHP
installed and configured to work with the server software?
If so, did you name the file correctly? It may need to be called "page.php"
rather than "page.html"...
M
On Thu, 7 Mar 2002, Michele wrote:
> I cur
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