chris smith-9 wrote:
>
> ddg2sailor wrote:
>>
>
>
>>It's still wrong regardless.
>
> I dont run the system , However the code I didnt post checks to make sure
> the user name or email isnt already in use or in fact was in use but
> removed. Diddnt have to bother with that part , it works fin
ddg2sailor wrote:
chris smith-9 wrote:
ddg2sailor wrote:
$row = mysql_fetch_array($res);
$res = mysql_query("SELECT passhash, editsecret, status FROM users WHERE
id
= $id");
$row = mysql_fetch_array($res);
I hope this is a copy/paste error or are you running the same thing twice?
I diddnt s
chris smith-9 wrote:
>
> ddg2sailor wrote:
>> $row = mysql_fetch_array($res);
>
>> $res = mysql_query("SELECT passhash, editsecret, status FROM users WHERE
>> id
>> = $id");
>> $row = mysql_fetch_array($res);
>
> I hope this is a copy/paste error or are you running the same thing twice?
>
>
ddg2sailor wrote:
Hi People
My real problem is that I dont know code. I can sort of edit it in a sloppy
more or less works fashion. Any help would be great.
This is the code Im having problems with:
//Example//
$id = 0 + $_GET["id"];
$md5 = $_GET["secret"];
$gig = 1;
$giveupload = $gig*1
Rob G wrote:
I'm working on this, and am not sure how the variable syntax needs to be
here.
This is what I have done manually.
//BEGIN EXAMPLE
mysql_query ("INSERT INTO testimonials (id, quote, name) VALUES ('$id_1',
'$entry_1', '$name_1')");
mysql_query ("INSERT INTO testimonials (id, quote,
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