On Fri, Feb 1, 2013 at 11:27 PM, tamouse mailing lists
wrote:
> On Fri, Feb 1, 2013 at 10:40 PM, Ron Piggott
> wrote:
>> In the following the “2.” means a moderator response and “25” is the account
>> # of the moderator.
>>
>> >
>> $author = 2.00025
>>
>> ?>
>>
>> How can I g
On Fri, Feb 1, 2013 at 11:40 PM, Ron Piggott wrote:
> How can I get the 25 by itself?
> - I want to drop the “2.” and remove all the zero’s
>
> Would it be best to turn this into a STRING?
>
I would recommend turning it into a string, splitting the string at the
decimal, then scanning the second
On Fri, Feb 1, 2013 at 10:40 PM, Ron Piggott
wrote:
> In the following the “2.” means a moderator response and “25” is the account
> # of the moderator.
>
>
> $author = 2.00025
>
> ?>
>
> How can I get the 25 by itself?
> - I want to drop the “2.” and remove all the zero’s
>
Suhas Pharkute wrote:
> Ok, I am sorry, but not sure what do you mean here?
the feeling is mutual.
it's rather like I asked you what color the sky is ... and you answered 'yes'.
> Is there any error?
>
> If so it will not even run the code
>
> Suhas
>
> On 6/21/07, Jochem Maas <[EMAIL PROTECT
Ok, I am sorry, but not sure what do you mean here? Is there any error?
If so it will not even run the code
Suhas
On 6/21/07, Jochem Maas <[EMAIL PROTECTED]> wrote:
Suhas Pharkute wrote:
> Hi,
>
> I tried to search on this mailing list and I saw the bug was reported
and
> fixed. I am using PH
On Thu, 2007-06-21 at 18:16 +0200, Tijnema wrote:
> On 6/21/07, Suhas Pharkute <[EMAIL PROTECTED]> wrote:
> > Hi,
> >
> > I tried to search on this mailing list and I saw the bug was reported and
> > fixed. I am using PHP 4.4.7 and GD 2
> >
> > The error that I am getting is at statement
> >
> > $i
Suhas Pharkute wrote:
> Hi,
>
> I tried to search on this mailing list and I saw the bug was reported and
> fixed. I am using PHP 4.4.7 and GD 2
you make it sound like there is only one bug.
>
> The error that I am getting is at statement
>
> $img_t = imagecreatetruecolor(100,100);*
On 6/21/07, Suhas Pharkute <[EMAIL PROTECTED]> wrote:
Hi,
I tried to search on this mailing list and I saw the bug was reported and
fixed. I am using PHP 4.4.7 and GD 2
The error that I am getting is at statement
$img_t = imagecreatetruecolor(100,100);*
Fatal error*: Possible integer overflow
On 3/23/07, Richard Lynch <[EMAIL PROTECTED]> wrote:
On Thu, March 22, 2007 2:33 pm, Tijnema ! wrote:
>> > 2). How do you handle numbers that large, while maintaining
>> precision.
>>
>> keep them as strings - and/or use a 64bit machine?
>
> a 64bit machine would make the number larger, not unli
On Thu, March 22, 2007 2:33 pm, Tijnema ! wrote:
>> > 2). How do you handle numbers that large, while maintaining
>> precision.
>>
>> keep them as strings - and/or use a 64bit machine?
>
> a 64bit machine would make the number larger, not unlimited :)
Even GMP (or BC) isn't unlimited...
It's jus
Tijnema ! wrote:
> On 3/22/07, Jochem Maas <[EMAIL PROTECTED]> wrote:
>> Matt Carlson wrote:
>> > When dealing with large numbers inside of php, I know at the int
>> limit, a variable is recast into float.
>> >
>> >
>> >
>> > 1). How do you return the true number of the float when it reaches
>> th
On 3/22/07, Jochem Maas <[EMAIL PROTECTED]> wrote:
Matt Carlson wrote:
> When dealing with large numbers inside of php, I know at the int limit, a
variable is recast into float.
>
>
>
> 1). How do you return the true number of the float when it reaches the upper
limits of mysql's bigint (92233
Matt Carlson wrote:
> When dealing with large numbers inside of php, I know at the int limit, a
> variable is recast into float.
>
>
>
> 1). How do you return the true number of the float when it reaches the upper
> limits of mysql's bigint (9223372036854775807).
I can't see how that is poss
On 3/22/07, Matt Carlson <[EMAIL PROTECTED]> wrote:
When dealing with large numbers inside of php, I know at the int limit, a
variable is recast into float.
1). How do you return the true number of the float when it reaches the upper
limits of mysql's bigint (9223372036854775807).
2). How
Thanx for the scripts! :-)
Appreciated!
/G
http://www.varupiraten.se/¨
- Original Message -
From: "Brian P. O'Donnell" <[EMAIL PROTECTED]>
To:
Sent: Wednesday, September 07, 2005 5:53 PM
Subject: Re: [PHP] Integer - boundary?
""M. Sokolewicz
""M. Sokolewicz"" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> or, easier, simply make this script:
> echo PHP_INT_MAX;
> ?>
>
> and you're done :P The maximum integer value is stored in PHP_INT_MAX as
> of 4.4.0 and PHP 5.0.5
>
> before that, you had to use a way as the one Bri
ot;PHP General"
Sent: Wednesday, September 07, 2005 5:03 PM
Subject: RE: [PHP] Integer - boundary?
-Original Message-
From: Gustav Wiberg [mailto:[EMAIL PROTECTED]
Hi there!
What is the boundary for an integer?
seems to be a easy question, but I can't find it...
""Gustav Wiberg"" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
>
> - Original Message -
> From: "Shaw, Chris - Accenture" <[EMAIL PROTECTED]>
> To: "Gustav Wiberg" <[EMAIL PROTECTED]>; "PHP Ge
- Original Message -
From: "Shaw, Chris - Accenture" <[EMAIL PROTECTED]>
To: "Gustav Wiberg" <[EMAIL PROTECTED]>; "PHP General"
Sent: Wednesday, September 07, 2005 5:03 PM
Subject: RE: [PHP] Integer - boundary?
-Original Messa
> -Original Message-
> From: Gustav Wiberg [mailto:[EMAIL PROTECTED]
>
> Hi there!
>
> What is the boundary for an integer?
>
> seems to be a easy question, but I can't find it...
>
> /G
> http://www.varupiraten.se/
>
According to the manual,
"The size of an integer is platform-de
excellent. thanks.
John W. Holmes wrote:
I know this seems easy, but I can't get it to work for the freaking
life
of me. I have number that is an integer, lets say 15, and I need it
to
be 15.00, for a monetary value. I've casted every which way to no
avail.
www.php.net/number_forma
> I know this seems easy, but I can't get it to work for the freaking
life
> of me. I have number that is an integer, lets say 15, and I need it
to
> be 15.00, for a monetary value. I've casted every which way to no
avail.
www.php.net/number_format
---John W. Holmes...
PHP Architect - A monthl
Try:
$n = $soils[$i];
$soils[$i] = sprintf("%d", $n);
and if that doesn't work, print out $soils[$i] to see what it is.
> -Original Message-
> $soils[$i] = sprintf("%d", $soils[$i]);
>
> But doesn't seem to work, my program returned an error.
> P.S. : I'm using 4.0.6 otherwise wouldn't
Hi,
Use intval("2.05");
I hope this will do the needful for you.
with regards,
Sukumar .S
On Mon, 21 Jan 2002, Jerry wrote:
> Date: Mon, 21 Jan 2002 13:35:34 -
> From: Jerry <[EMAIL PROTECTED]>
> To: [EMAIL PROTECTED]
> Subject: [PHP] Integer in PHP
>
> Hi,
>
> I'm new in PHP, comi
intval (2.05);
Valentin Petruchek (aki Zliy Pes)
http://zliypes.com.ua
mailto:[EMAIL PROTECTED]
- Original Message -
From: "Jerry" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, January 21, 2002 3:35 PM
Subject: [PHP] Integer in PHP
> Hi,
>
> I'm new in PHP, coming from Java
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
* On 21-01-02 at 14:34
* Jerry said
> Hi,
>
> I'm new in PHP, coming from JavaScript.
> In JavaScript you had the function parseInt which was really useful.
> For example parseInt("2.05") will return 2...
>
> How can I do that in PHP ?
Look
Because it's a string. You can use regex matching or test
whether floor($var) == $var, for example.
Steve
At 4/29/2001 04:25 AM, Jamie Saunders wrote:
>Hi,
>
>I'm submitting a phone number from an HTML form to a PHP page
>that examines it to see if it's an integer:
>
>form.html:
>
>validate.ph
It's a string, not an integer. Try using is_numeric() instead. To see
what type it is, do this :
echo gettype($phonenumber); // prints string
You may want to strip all non-numbers first, just in case they enter :
333-333-
Something like :
$phonenumber = preg_replace('/[^0-9]/','
Hi Todd!
if $a = 3.5 then
echo (int)$a // print 3
regards
Marcelo Gulin
Todd Cary escribió:
>
> What is the syntax for dividing 7 by 2 and getting 3; not 3.5?
>
> Todd
>
> --
> Todd Cary
> Ariste Software
> [EMAIL PROTECTED]
>
> --
> PHP General Mailing List (http://www.php.net/)
> What is the syntax for dividing 7 by 2 and getting 3; not 3.5?
you can use:
$intVar = ((int)( 7 / 2 ));
Chris
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