On Wed, August 1, 2007 1:23 am, Patrik Hasibuan wrote:
> This sql string produces proper output in my MySQL-Query:
> select image_src from products where product_id='10';
> the output is:
> gambarproduk/0/10/1.jpg
>
> But my php code does not produce anything.
>
> Please tell me what is my mistake.
Sorry, for my recklessness
I missed, "$bdku=mysql_select_db("guru",$konek);"
Es ist peinlich It's embarassing.
But thanks for your help.
=
On Wed, 1 Aug 2007 15:15:43 +0700
Patrik Hasibuan <[EMAIL PROTECTED]> wrote:
> Hi Sichta,
>
> That's what I am confused. Quoted or no Quote
Hi Sichta,
That's what I am confused. Quoted or no Quote makes no effect. mysql_query does
not work.
I tried to debug with "..or die (mysql_error());" but it seems "mysql_error()"
does not exist anymore.
Please keep telling me. I've wasted to much time today hanging around with this
weird pro
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