At 12:54 10-3-03, you wrote:
what problem I want to use eval in my script but its generate this error :
Parse error: parse error, unexpected T_LNUMBER in
C:\Projects\phpmag\admin\functions\admin_cont.php(22) : eval()'d code on line 4
eval ("\$all_types_list .= \"$all_types_list\";");
For tho
try
echo "\$all_types_list .= \"$all_types_list\";";
there should be a syntax error
Alawi wrote:
what problem I want to use eval in my script but its generate this error :
Parse error: parse error, unexpected T_LNUMBER in C:\Projects\phpmag\admin\functions\admin_cont.php(22) : eval()'d code on li
Felipe Coury wrote:
>
> Hi,
>
> I am a beginner in PHP and I am trying to do the following: I have a form in
> a page that has 3 fields: email_1, email_2 and email_3. I am trying to send
> e-mail to those people, if the fields are filled. Relevant part of code:
>
> for ($i = 1; $i <= 6; $i++)
lots of things:
1) variables in single-quoted strings aren't evaluated so you don't
need to escape the $ in $email
2) php uses . not + for concatenation.
3) try it like this:
eval('$email = $email_'.$i.';');
or
eval("\$email = \$email_$i;");
4) you can save yourself the trouble by using arrays
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