Re: [PHP] Environment extract

2001-03-27 Thread Philip Olson
Ahh, that's the cause. Here's how to duplicate the error :-) error_reporting(E_NOTICE); foo(); function foo() { echo $HTTP_USER_AGENT; } As Mark mentioned, mind your scope. Regarding the error, I just posted some information on this perhaps it'll be of some use : http://mar

Re: [PHP] Environment extract

2001-03-27 Thread Mark Maggelet
On Tue, 27 Mar 2001 17:31:25 +0100, Costas ([EMAIL PROTECTED]) wrote: >when i try printing > >print $HTTP_USER_AGENT; > >I get the error message Undefined variable: HTTP_USER_AGENT > >have i missed a declaration of some sort or something else? > >thanks Are you doing this from inside a function

Re: [PHP] Environment extract

2001-03-27 Thread Costas
when i try printing print $HTTP_USER_AGENT; I get the error message Undefined variable: HTTP_USER_AGENT have i missed a declaration of some sort or something else? thanks ""Matt Friedman"" <[EMAIL PROTECTED]> wrote in message 002701c0b6d8$88abb740$03284d18@mattq3h8budilr">news:002701c0b6d8$8

Re: [PHP] Environment extract

2001-03-27 Thread Matt Friedman
print $HTTP_USER_AGENT; // the variable is already in the global scope. also $ua = getenv('HTTP_USER_AGENT'); Most variables are automatically made a part of the environment in a PHP script. It's one of the ways PHP makes scripting easier. The online manual is invaluable for this type of info.