print $buildingPath . '';
if (opendir($buildingPath) == false)
if (!mkdir($buildingPath))
print 'false ';
A print("false $buildingPath") might yield as to why it isn't
creating it.
I already di
On Monday, September 1, 2003, at 03:41 PM, Curt Zirzow wrote:
print $buildingPath . '';
if (opendir($buildingPath) == false)
if (!mkdir($buildingPath))
print 'false ';
A print("false $buildin
* Thus wrote Seth Willits ([EMAIL PROTECTED]):
>$path = "path/path2/path3/path4/path5";
> $buildingPath = "existingFolder";
> $pathComponents = split("/", $path);
>
>
> foreach ($pathComponents as $value) {
> $buildingPath = $buildingPath . "/" . $val
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