Richard Lynch wrote:
> On Mon, December 18, 2006 7:09 am, Nisse Engström wrote:
>> On Fri, 15 Dec 2006 23:22:13 -0600 (CST), "Richard Lynch" wrote:
>>
>>> $selected = $l == $limit ? 'selected="selected"' : '';
>>> echo "$l\n";
>> [snip]
>>
>>> The value="x" *is* optional, but you'll never
On Mon, December 18, 2006 7:09 am, Nisse Engström wrote:
> On Fri, 15 Dec 2006 23:22:13 -0600 (CST), "Richard Lynch" wrote:
>
>> $selected = $l == $limit ? 'selected="selected"' : '';
>> echo "$l\n";
>
> [snip]
>
>> The value="x" *is* optional, but you'll never convince the people
>> who
>
On Fri, 15 Dec 2006 23:22:13 -0600 (CST), "Richard Lynch" wrote:
> $selected = $l == $limit ? 'selected="selected"' : '';
> echo "$l\n";
[snip]
> The value="x" *is* optional, but you'll never convince the people who
> tell you it isn't, unless you force them to read the RFCs and W3C
> re
On Tue, December 12, 2006 2:14 am, William Stokes wrote:
> Can someone tell me what wrong or to how to manage this?
>
> //default
> $limitorig = 10;
>
> echo "";
> echo "$limitorig";
> echo "10";
> echo "20";
> echo "30";
> echo ";
$l\n";
}
?>
The value="x" *is* optional, but you'll never c
William Stokes wrote:
Hello,
Can someone tell me what wrong or to how to manage this?
//default
$limitorig = 10;
echo "";
echo "$limitorig";
echo "10";
echo "20";
echo "30";
echo ";
Something like this would be better:
$limitorig = 10;
$options = array('10', '20', '30');
if (isset($_POST['
William Stokes wrote:
> Hello,
>
> Can someone tell me what wrong or to how to manage this?
>
> //default
> $limitorig = 10;
>
> echo "";
> echo "$limitorig";
^^ what do you think $_POST['USRlimitorig'] will
be if you select the first option?
> echo "10";
> echo
William Stokes wrote:
Hello,
Can someone tell me what wrong or to how to manage this?
//default
$limitorig = 10;
echo "";
echo "$limitorig";
echo "10";
echo "20";
echo "30";
echo ";
firstly its better to use 10
this might also solve your problem if I understand your question correctly.
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