RE: [PHP] variable issue

2001-11-09 Thread Clint Tredway
thanks for all the help. I realized that I did not need the else, and the isset() works great! Now I have my calendar working the way I want it to! Thanks! Clint -- Original Message -- From: "Matthew Luchak" <[EMAIL PROTECTED]> Date: Fri, 9 Nov 2001 15:07

RE: [PHP] variable issue

2001-11-09 Thread Matthew Luchak
if(!isset($dte)) { $dte=date("j", time()+$ctime);} You don't need the else statement. Matthew Luchak Webmaster Kaydara Inc. [EMAIL PROTECTED] -Original Message- From: Clint Tredway [mailto:[EMAIL PROTECTED]] Sent: Friday, November 09, 2001 2:37 PM To: PH

Re: [PHP] variable issue

2001-11-09 Thread R'twick Niceorgaw
replace the if statement if(!$dte) with if (!isset($dte)) - Original Message - From: "Johnson, Kirk" <[EMAIL PROTECTED]> To: "PHP General" <[EMAIL PROTECTED]> Sent: Friday, November 09, 2001 2:35 PM Subject: RE: [PHP] variable issue > The else cla

RE: [PHP] variable issue

2001-11-09 Thread Johnson, Kirk
The else clause can be removed, since it is not doing anything. What is the error message? Kirk > Hey everyone, I need some help with a variable issue. How can > I delcare a variable and then if a url variable of the same > name is present use that value instead? > > this is what I have: > if