Dan Joseph wrote:
Sometimes there won't be anything to replace at the front, and sometimes
nothing at the end. So it'd still need to do the front and/or end wether or
not they both exist.
Is there a way to tweak these to do that?
Question:
Where is this number coming from? Couldn't you j
Dan Joseph wrote:
From John:
$new_number =
preg_replace('/^'.$this->start_num.'([0-9]+)'.$this->end_num.'$/',
'\\1',$old
_number);
The one that Mike gave didn't seem to do anything, John's will work if it
can match the beginning and the end successfully. I should probably explain
myself
From: "Dan Joseph" <[EMAIL PROTECTED]>
> I've searched the high heavens for a method of doing this... Here's what
> I'm doing... First, the code..
>
> $middlenum = preg_replace("/^".$this->start_num."/", "",
> $this->ach_acct_num);
> $middlenum = preg_replace("/".$this->end_num."$/", "", $middlenu
Hi,
> > In a nutshell, what I want to do is chop off the front and the back.
> > Example:
> >
> > I have: 1234567890
> > I want: 456
> >
> > I have a start num and an end num. start = 123, end = 7890.
> >
> > This is working fine as I have it above, however I'd like to combine
> > it into one reg
Dan Joseph wrote:
Question:
Where is this number coming from? Couldn't you just use a substr() based
upon it's length and not deal with a regular expression?
Its a bank account number coming from a database. We're reformatting it
for ACH processing. The number could be:
23408234980423
Hi,
> Not tested, mind you. I know what you're saying, too. How is _all_ of
> that code better(worse?) than one simple regex? Benchmark it and see.
> You'll be surprised how a lot more code with simple string functions
> will be considerably faster than a complex regular expression. Your
> results
On 08 August 2003 15:39, Dan Joseph wrote:
> I've searched the high heavens for a method of doing this...
> Here's what
> I'm doing... First, the code..
>
> $middlenum = preg_replace("/^".$this->start_num."/", "",
> $this->ach_acct_num); $middlenum =
> preg_replace("/".$this->end_num."$/", "", $m
Hi,
> Question:
> Where is this number coming from? Couldn't you just use a substr() based
> upon it's length and not deal with a regular expression?
Its a bank account number coming from a database. We're reformatting it
for ACH processing. The number could be:
23408234980423
On 08 August 2003 17:39, Dan Joseph wrote:
> Hi,
>
> > > In a nutshell, what I want to do is chop off the front and the
> > > back. Example:
> > >
> > > I have: 1234567890
> > > I want: 456
> > >
> > > I have a start num and an end num. start = 123, end = 7890.
> > >
> > > This is working fi
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