On Wed, April 20, 2005 7:22 am, Bob Palma said:
> I have a database field that I need to read and do some conversion on.
> Here is what the raw data from the database looks like:
>
> --
> 1084751309jpenaDisney Vignette Fleximon disk utilization
> alert C:\ at 85%1084799703bpalmafixed.10847997
Thanks. I took a look, and you were right. It was creating another
entry in the array at the end, so I used an if statement checking the
value of [1] and [2] in $array_of_fields.
Thanks for all the great help
Bob Palma
[EMAIL PROTECTED]
Duncan Hill wrote:
On Wednesday 20 April 2005 16:01,
On Wednesday 20 April 2005 16:01, Bob Palma typed:
> Wow! Thanks.. That works great. Just one small hitch though. After it
> prints all of the data properly, it adds one more '$date' on the end
> which gets printed as '12/31/69 7:00:pm'. Is there a way to do all
> groups - 1 ?
No reason for it
Wow! Thanks.. That works great. Just one small hitch though. After it
prints all of the data properly, it adds one more '$date' on the end
which gets printed as '12/31/69 7:00:pm'. Is there a way to do all
groups - 1 ?
Bob Palma
[EMAIL PROTECTED]
Duncan Hill wrote:
On Wednesday 20 April 200
On Wednesday 20 April 2005 15:22, Bob Palma typed:
> I have a database field that I need to read and do some conversion on.
> Here is what the raw data from the database looks like:
>
> --
> 1084751309jpenaDisney Vignette Fleximon disk utilization
> alert C:\ at 85%1084799703bpalmafixed.10847
[snip]
I'm trying to replace a substr of the string that start from "Rated
blahblah;" azt the end semicolon.
Example:
safsagfasdfsdfdsfRated by 4 people;fafafaafafaf -> return
safsagfasdfsdfdsffafafaafafaf
$replacement ="";
$pattern = "/Rated.+;/";
$found_str = preg_replace($pattern, $replaceme
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