mysql_fetch_array($Results);
if (isset($Row))
print $Row[0] . "";
}
print "";
}
print "";
-Original Message-
From: Jason Soza [mailto:[EMAIL PROTECTED]]
Sent: Thursday, July 11, 2002 3:18 PM
To: Lazor, Ed
Cc: [EMA
Kevin
- Original Message -
From: "Jason Soza" <[EMAIL PROTECTED]>
To: "Michael Davey" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Thursday, July 11, 2002 3:43 PM
Subject: Re: [PHP] Re: Table Making
> I really wish I was at home right now so I could test
ific date.
I'm hoping the code I posted will create something like:
1941
1942
1943
...
Make sense?
Jason Soza
- Original Message -
From: "Lazor, Ed" <[EMAIL PROTECTED]>
Date: Thursday, July 11, 2002 2:08 pm
Subject: RE: [PHP] Re
Will this work for you?
$numFields = mysql_num_fields($Results);
print "";
while ($Row = mysql_fetch_array($Results))
{
print "";
for ($i = 0; $ < $numFields; $i++)
print "".$Row[$i]."";
I really wish I was at home right now so I could test this out... I'll
certainly give this a shot tonight. Taking someone else's earlier
suggestion and tweaking it a bit, I was wondering if the following
might work:
$cells = 10; //set desired number of cells per column
$numRows = mysql_num_row
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