Re: [PHP] Math rounding problem

2002-02-08 Thread hugh danaher
ceil() maybe - Original Message - From: "Charlie Killian" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Friday, February 08, 2002 4:14 PM Subject: [PHP] Math rounding problem > For an arbitrary large number I need to round() it up to the hundreds place > if it is not divisible by 100

RE: [PHP] Math rounding problem

2002-02-08 Thread Charlie Killian
This equation from Bogdan is simple and working: $scale=ceil($scale/100)*100; Thanks to all those who helped, Charlie > -Original Message- > From: Bogdan Stancescu [mailto:[EMAIL PROTECTED]] > > $scale=ceil($scale/100)*100, maybe? > > Bogdan -- PHP General Mailing List (http://ww

Re: [PHP] Math rounding problem

2002-02-08 Thread DL Neil
Charlie, > For an arbitrary large number I need to round() it up to the hundreds place > if it is not divisible by 100 and leave it untouched if it is. > > So 1100 would round to 1100 and > 1101 would round to 1200. > > Is there a clean way to do this? > > Currently I'm: > $scale = round($scal