- Original Message -
> function showpix($picture_id)
> {
> $sql="SELECT ug.group_name, p.name from usenet_groups as ug,
> pictures as p WHERE p.id='$picture_id' AND ug.id=p.group_id";
> $result=mysql_query($sql) or die(mysql_error());
> $row=mysql_fetch_ar
It worked!! but only after I removed the two blank lines above the
To: <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Thursday, August 09, 2001 3:40 PM
Subject: RE: [PHP] Image header problems
> Remove the line:
>
> print "jpeg format";
>
> The error i
Remove the line:
print "jpeg format";
The error is because you have sent output to the browser before you are
trying to send a header.
-Original Message-
From: Hugh Danaher [mailto:[EMAIL PROTECTED]]
Sent: 09 August 2001 23:26
To: Php-General
Subject: [PHP] Image header problems
I wa
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