Richard Davey wrote:
Hello André,
Wednesday, July 6, 2005, 3:25:37 PM, you wrote:
AM> Depending on the sittuation, IMHO, COUNT(*) wouldn't be the way to
AM> go. If you need the user's id or somesuch, you have to run an
AM> additional query to get the info.
But they're returning absolutely noth
have to agree with Richard here, its wasting resources bringing back *
from the database. Its one of those fundamentals. Only do a select *
from... where you actually need all the info.
Bill, try read the manual to see how the |mysql_query() returns info.
SOmeone has posted the link in this threa
On Wed, 2005-07-06 at 14:12 +0100, Richard Davey wrote:
> Hello Bill,
>
> Wednesday, July 6, 2005, 3:36:09 AM, you wrote:
>
> BM> I'm working my way through IBM's PHP tutorial. Generally good ...
> BM> but I'm stuck at an error point and have no idea what's going
> BM> wrong. Before adding a new
Bill McEachran wrote:
Newbie question.
I'm working my way through IBM's PHP tutorial. Generally good ... but
I'm stuck at an error point and have no idea what's going wrong.
Before adding a new row to the mysql database (already opened) we do a
query to see if a particular record already exis
Hello Bill,
Wednesday, July 6, 2005, 3:36:09 AM, you wrote:
BM> I'm working my way through IBM's PHP tutorial. Generally good ...
BM> but I'm stuck at an error point and have no idea what's going
BM> wrong. Before adding a new row to the mysql database (already
BM> opened) we do a query to see if
[snip]
We then test, using if, to see if $resultT is true or false. If it's
false we are then supposed to enter a new record.
Problem: it's never false. It always evaluates true. What am I doing
wrong? TIA
/* build query to see if the record is entered already */
$sqlT = "select * f
On Tue, 2005-07-05 at 22:36 -0400, Bill McEachran wrote:
> Newbie question.
>
> I'm working my way through IBM's PHP tutorial. Generally good ... but
> I'm stuck at an error point and have no idea what's going wrong.
> Before adding a new row to the mysql database (already opened) we do a
> que
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