Re: [PHP] Error Code Airhead

2004-11-02 Thread Jennifer Goodie
-- Original message -- From: Jeff Oien <[EMAIL PROTECTED]> > //always gives error message even if one of the two codes entered: > if ($Promotion_Sub == 'Checked' && ($code != 'D04E' || $code != 'Y04KG')) { If $code is D04K then it is not Y04KG making the statement

RE: [PHP] Error Code Airhead

2004-11-02 Thread Pablo Gosse
[snip] > I'm sure I'm missing something really obvious here but > can't see it. There is a form where one of two promotional codes can > be entered. I check for the these codes and give the user an error > message if they enter the wrong code. First one doesn't work, second > one does with only one

Re: [PHP] Error Code Airhead

2004-11-02 Thread Greg Donald
On Tue, 02 Nov 2004 12:17:45 -0600, Jeff Oien <[EMAIL PROTECTED]> wrote: > if ($Promotion_Sub == 'Checked' && ($code != 'D04E' || $code != 'Y04KG')) { ($code != 'D04E' || $code != 'Y04KG') Since $code cannot equal two different values at once, this will always evaluate to true. Maybe you meant &