RE: [PHP] Date addition problem

2006-03-29 Thread Weber Sites LTD
Date of today +1 .. +x days http://www.weberdev.com/get_example-292.html Sincerely berber Visit the Weber Sites Today, To see where PHP might take you tomorrow. SEO Data Monitor http://seo.weberdev.com -Original Message- From: Adrian Bruce [mailto:[EMAIL PROTECTED] Sent: Wednes

Re: [PHP] Date addition problem

2006-03-29 Thread tedd
Hi: The problem is that you have transposed your date elements. See this: http://xn--ovg.com/a3.php Try this code: date test (d/m/y)"; $start = "05-09-07"; $start = explode('-',$start); $startmk = mktime(0,0,0,$start[1],$start[0],$start[2]); $startdate = date('d-m-y',$startmk); print_r($sta

RE: [PHP] Date addition problem

2006-03-29 Thread Ford, Mike
> -Original Message- > From: Adrian Bruce [mailto:[EMAIL PROTECTED] > Sent: 29 March 2006 13:52 > > I am having an unusual problem when trying to calculate dates > in advance > from a start date. the code below shows a loop where by on > each run an > increasing number of weeks is ad

Re: [PHP] Date addition problem

2006-03-29 Thread Adrian Bruce
I have come up with an alternative myself but still cant explain why the first method did not work, still be interested to know why if anyone can offer some thoughts. Using strtotime for the calc seems to produce correct results my soluiton: [snip] date test 2"; $start = "05-09-07"; $start

Re: [PHP] Date addition problem

2006-03-29 Thread Adrian Bruce
That should not effect it, if i am adding $i * 7 days each time then i should get the date that comes 7 days later irrespective of how many days are in the month, shouldn't I ? 8 * 7 = 56, 56 days after the 07-09-05 is 02-11-2005. Thomas Munz wrote: Cause 9th month have 30 days but 10th mont

Re: [PHP] Date addition problem

2006-03-29 Thread Thomas Munz
Cause 9th month have 30 days but 10th month have 31 days. You don't check the amount of day there... :) on Wednesday 29 March 2006 14:51, Adrian Bruce wrote: > Hi > > I am having an unusual problem when trying to calculate dates in advance > from a start date. the code below shows a loop where