John W. Holmes wrote:
Tony wrote:
Trying to use the following statement to upload a file via a form,
when I use a variable "$foo" in the following statement it works
correctly:
if (copy($foo, "./$foo_name")) {//blah... }
The name of the file I am trying to upload $foo is evaluated correctly.
Lik
Tony wrote:
Trying to use the following statement to upload a file via a form, when
I use a variable "$foo" in the following statement it works correctly:
if (copy($foo, "./$foo_name")) {//blah... }
The name of the file I am trying to upload $foo is evaluated correctly.
Likewise I can obtain the
Trying to use the following statement to upload a file via a form, when
I use a variable "$foo" in the following statement it works correctly:
if (copy($foo, "./$foo_name")) {//blah... }
The name of the file I am trying to upload $foo is evaluated correctly.
Likewise I can obtain the file size, "
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