Folks,
I upgraded from PHP 5.2.6 to 5.3.1 on my test machine. Pretty easy, just
installed FastCGI for IIS6, installed PHP 5.3.1 and entered the .php ext
stuff into IIS6.
Now I tried it on my production box. No go. Although the web extension
"FastCGI Handler" can be enabled with no problems, PHP d
I thing, you must use
$s = getenv('SCRIPT_URL'); and not $s = getenv('SCRIPT_NAME'); in php ver 4.3.2
Shaun wrote:
Hi,
The following code snippet is supposed to return the current page i am on
and append some variables.
$s = getenv('SCRIPT_NAME');
$link = "$s?month=$month&year=$year&goto_da
* Thus wrote Shaun ([EMAIL PROTECTED]):
> Hi,
>
> The following code snippet is supposed to return the current page i am on
> and append some variables.
>
> $s = getenv('SCRIPT_NAME');
> $link = "$s?month=$month&year=$year&goto_date=yes";
>
> However, since upgrading to PHP version 4.3.2 it retu
Hi,
The following code snippet is supposed to return the current page i am on
and append some variables.
$s = getenv('SCRIPT_NAME');
$link = "$s?month=$month&year=$year&goto_date=yes";
However, since upgrading to PHP version 4.3.2 it returns the following URL:
execscriptdir/php.cgi?day=19&month
Hi, I have been running 4.0.3 or so and I was upgrading to 4.1.1.
I also upgraded gdlib to 1.8.4. I compiled php with jpeg support and gd
support
everything made and compiled ok.
when I restart apache I get this:
Setting up Web Service: Syntax error on line 58 of
/etc/httpd/conf/httpd.conf:
C
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