>
>- Original Message -----
>From: "Martin Towell" <[EMAIL PROTECTED]>
>To: "GENERAL PHP LIST" <[EMAIL PROTECTED]>
>Sent: Wednesday, November 14, 2001 3:19 AM
>Subject: RE: [PHP] take date and convert to day of year
>
>
>>I&#x
mp as you did in your earlier codes.
- Original Message -
From: "Martin Towell" <[EMAIL PROTECTED]>
To: "GENERAL PHP LIST" <[EMAIL PROTECTED]>
Sent: Wednesday, November 14, 2001 3:19 AM
Subject: RE: [PHP] take date and convert to day of year
> I'm r
L PHP LIST
Subject: Re: [PHP] take date and convert to day of year
I have tried to implement your code Martin, and I do thank you VERY MUCH
for the help, but your code seems to have the same trouble as mine, it
doesn't matter what date I start with, I end up with 364 as the day of
the year
;];
>print $dobnum;
>
>Notice I changed the format of the date, when I tried using the original
>format, strtotime() complained, saying it couldn't convert it.
>
>Martin T
>
>-----Original Message-
>From: sundogcurt [mailto:[EMAIL PROTECTED]]
>Sent: Wednesday, November
tried using the original
format, strtotime() complained, saying it couldn't convert it.
Martin T
-Original Message-
From: sundogcurt [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, November 14, 2001 7:57 AM
To: GENERAL PHP LIST
Subject: [PHP] take date and convert to day of year
Hi guys, I
Hi guys, I know that you can take todays date and display it as the
numeric day of the year, 1 - 365 / 0 - 364 etc.
But can you take a date such as (November-30-1971) and convert that to
the numeric day of the year?
I have been trying to do this but have had no joy, I don't think my code
is ev
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