Re: [PHP] subtitute of mysql_error()

Whatever made you think mysql_error() wasn't working, that was wrong. Because mysql_error() works just fine. On Wed, August 1, 2007 1:09 am, Patrik Hasibuan wrote: > Dear my friends > > What is the substitute of mysql_error() ? > > This line of my code does not work anymore: > $

Re: [PHP] subtitute of mysql_error()

Patrik Hasibuan wrote: Dear my friends What is the substitute of mysql_error() ? This line of my code does not work anymore: $hslgbr=mysql_query("$sqlgbr","$konek") or die ( mysql_error() ); Thank you very much in advance. In what way does it "not work anymore"? The cod

[PHP] subtitute of mysql_error()

Dear my friends What is the substitute of mysql_error() ? This line of my code does not work anymore: $hslgbr=mysql_query("$sqlgbr","$konek") or die ( mysql_error() ); Thank you very much in advance. -- Patrik Hasibuan <[EMAIL PROTECTED]> Junior Programmer -- PHP General