Re: [PHP] simple yet weird... help pls

> Please take a look at the script below. > If i want to show an image it doesnt work if it's under an if statement. > Why in this case? > > $feedb=0; > if($feedb==0){ echo "";} > echo ""; > ?> > How can i solve this problem? By spelling src correctly. -Rasmus --

[PHP] simple yet weird... help pls

Please take a look at the script below. If i want to show an image it doesnt work if it's under an if statement. Why in this case? ";} echo ""; ?> How can i solve this problem? thank you! Simon -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www