On 30 Oct 2005, at 14:13, John Taylor-Johnston wrote:
echo $contents;
PHP doesn't now that it's PHP - it just treats it as text. You can
tell it to run it as PHP explicitly using:
eval($contents);
Eval is usually worth avoiding, but it will do what you ask.
Your display function could be
I have some html + php stored in a mysql record. But when I echo the
contents:
$mydata->HTML="";
the php is not activated; rather I see in my html source.
It worked before, I thought.
P.S. is there a better way to use this function?
John
snip-
display();
echo $contents;
f
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