APseudoUtopia wrote:
> On Mon, Mar 22, 2010 at 5:13 PM, Peter van der Does
> wrote:
>> On Mon, 22 Mar 2010 16:58:33 -0400
>> APseudoUtopia wrote:
>>
>>> Hey list,
>>>
>>> I have a very odd problem which has been driving me crazy for two
>>> days. I've been trying to debug my code and gave up. I f
On Mon, Mar 22, 2010 at 5:13 PM, Peter van der Does
wrote:
> On Mon, 22 Mar 2010 16:58:33 -0400
> APseudoUtopia wrote:
>
>> Hey list,
>>
>> I have a very odd problem which has been driving me crazy for two
>> days. I've been trying to debug my code and gave up. I finally coded a
>> very simple re
On Mon, 22 Mar 2010 16:58:33 -0400
APseudoUtopia wrote:
> Hey list,
>
> I have a very odd problem which has been driving me crazy for two
> days. I've been trying to debug my code and gave up. I finally coded a
> very simple representation of what the code does, and I get the same
> problem. How
On Mon, Mar 22, 2010 at 4:58 PM, APseudoUtopia wrote:
> Hey list,
>
> I have a very odd problem which has been driving me crazy for two
> days. I've been trying to debug my code and gave up. I finally coded a
> very simple representation of what the code does, and I get the same
> problem. However
Hey list,
I have a very odd problem which has been driving me crazy for two
days. I've been trying to debug my code and gave up. I finally coded a
very simple representation of what the code does, and I get the same
problem. However, I still don't understand what's causing it.
The representationa
On Tuesday 01 April 2003 11:59, Sebastian wrote:
> Hmm, interesting.. i dunno why it doesn't work for me, here is a bit of the
> code, $var isn't getting the output of $id, any ideas?
Are you sure that $id contains what you think it contains?
Also could you explain the reason why your code is lai
Hmm, interesting.. i dunno why it doesn't work for me, here is a bit of the
code, $var isn't getting the output of $id, any ideas?
$var = &$id;
if( ! $forg = resizer_main("image","image_$var", blah, blah");
$org = getimagesize( "$root/$forg" );
$result = @mysql_query("INSERT INTO imag
Putting an & sign in front of the $id in the first line should do the trick:
$variable = &$id;
A short example:
$bar = 0;
$foo = &$bar;
$bar = 2;
print $foo; //prints 2
__
Marcus Rasmussen
[EMAIL PROTECTED]
www.marcusr.dk
Hi Sebastian,
> $variable = $id;
> // some other stuff
> @mysql_query here
> $id = mysql_insert_id();
>
> How do I get $id from insert_id() to pass to $variable
> above? Hard to explain the situation i am in, but the
> query has to be below $variable
::blink::
Perhaps something like:
hello all,
$variable = $id;
// some other stuff
@mysql_query here
$id = mysql_insert_id();
to the question: How do I get $id from insert_id() to pass to $variable
above? Hard to explain the situation i am in, but the query has to be below
$variable, is it possible to 'globalize' $id so
Hello,
here is my problem :
I have a class A and I instanciate this class at the beginninf of my script.
I have another class B and in some functions of this class B, I need to
access the instance of the class A.
So in the functions of the class B, to access the class A, is it better to
receive a
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