Re: [PHP] first time using exec() - are getting parse error.

What is the error you get? Problem solved: it was a combination of permissions and wrong options. -- anders thoresson -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

Re: [PHP] first time using exec() - are getting parse error.

anders thoresson wrote: Hi, I'm trying to call mysqldump from within a php-script, like this: $backuptime = date("ymdHi"); $backupfile = "un" . $backuptime . ".txt"; exec("mysqldump --opt -u$dbuser -p$dbpassword $dbdatabase $alltables > /web/un/backup/$backupfile"); It works fine on my local

Re: [PHP] first time using exec() - are getting parse error.

At 12:06 17-8-2003, you wrote: Hi, I'm trying to call mysqldump from within a php-script, like this: $backuptime = date("ymdHi"); $backupfile = "un" . $backuptime . ".txt"; exec("mysqldump --opt -u$dbuser -p$dbpassword $dbdatabase $alltables > /web/un/backup/$backupfile"); It works fine on my lo

[PHP] first time using exec() - are getting parse error.

Hi, I'm trying to call mysqldump from within a php-script, like this: $backuptime = date("ymdHi"); $backupfile = "un" . $backuptime . ".txt"; exec("mysqldump --opt -u$dbuser -p$dbpassword $dbdatabase $alltables > /web/un/backup/$backupfile"); It works fine on my local Win2k, php 4.3.1, but not