> This leads me to another question. If I have stored the date as an
> epoch then is there a way using PHP and MySQL to say find all the
> records that have been added this YEAR (not last 365 days)?
SELECT * FROM table WHERE YEAR(FROM_UNIXTIME(column)) =
YEAR(CUR_DATE());
Benchmark each method an
Caught that :) Thanks for the tip... worked just perfect (after I fixed
typo)
On Friday, March 28, 2003, at 12:57 AM, Foong wrote:
sorry
typo error should be:
date('Y')
Foong
"Foong" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
hi,
$start = mktime ( 0, 0, 0, 1, 1, date['Y']);
sorry
typo error should be:
date('Y')
Foong
"Foong" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> hi,
>
> $start = mktime ( 0, 0, 0, 1, 1, date['Y']); // first day of this year
> $end = mktime ( 0, 0, 0, 12, 31, date['Y']); // last day of this year
>
> then select all record wh
hi,
$start = mktime ( 0, 0, 0, 1, 1, date['Y']); // first day of this year
$end = mktime ( 0, 0, 0, 12, 31, date['Y']); // last day of this year
then select all record where timestamp >= $start and timestamp <= $end
should do the job
Hope this helps
Foong
"Charles Kline" <[EMAIL PROTECTED
Okay cool.
This leads me to another question. If I have stored the date as an
epoch then is there a way using PHP and MySQL to say find all the
records that have been added this YEAR (not last 365 days)?
Thanks
Charles
On Friday, March 28, 2003, at 12:31 AM, Leo Spalteholz wrote:
On March 27,
I think there's problems doing that when daylight savings starts/ends
Just something to keep in mind...
-Original Message-
From: Leo Spalteholz [mailto:[EMAIL PROTECTED]
Sent: Friday, March 28, 2003 4:32 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] date math question
On March 27, 20
On March 27, 2003 09:15 pm, Charles Kline wrote:
> I am storing my dates as unix timestamp (epoch). Am I right in
> assuming that if I need to add or subtract days from this it is
> done in seconds?
yes
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I am storing my dates as unix timestamp (epoch). Am I right in assuming
that if I need to add or subtract days from this it is done in seconds?
So for example if I have the timestamp 1041397200 and I wanted to
subtract 24 hours from it I would do this:
$newtime = $orig_time - 86400;
Thanks,
Ch
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