Re: [PHP] Way to test if variable contains valid date

2012-07-03 Thread Erwin Poeze
Or you could use a regular expression: $probe = '2000-01-01'; $found = preg_match('/(19|20)\d\d[- \.](0[1-9]|1[012])[- \.](0[1-9]|[12][0-9]|3[01])/', $probe); var_dump($found==1); Erwin 2012/7/3 shiplu > > > > > > I want to thank you, Daniel, for this help. - I was looking for an > > "isarray

Re: [PHP] Way to test if variable contains valid date

2012-07-03 Thread shiplu
> > > I want to thank you, Daniel, for this help. - I was looking for an > "isarray" type function There is no such function or facility in php. However you can check date in string by DateTime object also try { $date = new DateTime('2000-01-01'); } catch (Exception $e) { echo $e->getMe

Re: [PHP] Way to test if variable contains valid date

2012-07-02 Thread Ron Piggott
On Mon, Jul 2, 2012 at 2:54 PM, Ron Piggott wrote: Is there a way to test a variable contains a valid date - 4 digits for the year - 2 digits for the month (including leading 0) - 2 digits for the day (including leading 0) OR - a function? You may want to check out checkdate(): h

Re: [PHP] Way to test if variable contains valid date

2012-07-02 Thread Daniel Brown
On Mon, Jul 2, 2012 at 2:54 PM, Ron Piggott wrote: > > Is there a way to test a variable contains a valid date > - 4 digits for the year > - 2 digits for the month (including leading 0) > - 2 digits for the day (including leading 0) > > OR > > - a function? You may want to check out checkdate