ok - my latest in the eval saga is this:
I want to be able to eval a function call anywhere in the string supplied,
and the function call is not in scope when the string is defined.
So
-- somewhere in my code I wanted something like this:
$string = "testing nodename: \$node->getName()
pagename:
we're in the pipe, 5-5-5.");
$str = "Hello, \$name";
$str2 = "Hello, \$arr[0]";
$str3 = "Hello, \$arr2[".NAME_TAG."]";
echo doEvalWithVarsInScope($str);
echo doEvalWithVarsInScope($str2);
echo doEvalWithVarsInScope($str3);
}
function doEvalWithVarsInScope($str)
{
echo("trying to e
Actually, I just realised that what I want to accomplish is different from
my example - the main issue is with scope:
we're in the pipe, 5-5-5.");
$str = "Hello, \$name";
$str2 = "Hello, \$arr[0]";
$str3 = "Hello, \$arr2['name']";
echo doEvalWithVarsInScope($str);
echo doEvalWithVarsI
Thanks Dan - I just worked this out before reading your solution! :)
$str4 = "Hello, ".$arr2['name'];
cheers and thanks to all - lets see how that goes within my framework now :)
neko
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Hi,
> $arr2["name"] = "Broness!";
..
> $str3 = "Hello, $arr2['name']";
..
> eval ("\$evaldString = \"$str3\";");
> echo $evaldString;
Your almost there... just remember one very simple rule - if in doubt,
break out. Meaning, if you're having variable resolution issues, then just
break out of the
note that the following php:
Hello, $name";
$str2 = "Hello, $arr[0]";
$str3 = "Hello, $arr2['name']";
eval ("\$evaldString = \"$str\";");
echo $evaldString;
eval ("\$evaldString = \"$str2\";");
echo $evaldString;
eval ("\$evaldString = \"$str3\";");
echo $evaldString;
?>
produces:
Broness!He
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