Curt Zirzow wrote:
$userid = (int) $_POST['TXT_UserID'];
$sql = "... WHERE UserID = $userid";
Seing that I have a question around. Most cases I validate the $userid
by using the function inval() in that way:
$userid = inval($_POST['TXT_UserID'];
$sql = "... WHERE UserID = $userid";
I
* Thus wrote Torsten Roehr:
> "Harlequin" <[EMAIL PROTECTED]> wrote in message
> news:[EMAIL PROTECTED]
> > Another day another problem. This time it appears that users are able to
> > enter their details but I get a query execution error with the following
> > section of code:
> >
> > /* Verify Lo
"Harlequin" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Another day another problem. This time it appears that users are able to
> enter their details but I get a query execution error with the following
> section of code:
>
> /* Verify Login */
> $sql = "SELECT UserFirstName,Us
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