[PHP] Re: Pipe $var to a shell command

2003-06-13 Thread Tim T
YYYEE! Finally - It works!! I used the following: $fp = popen("$mycommand", "w+"); fwrite($fp, $myoutput); Thank you for your assistance. I've been looking at this for 2 days and nothing was coming to mind! Again thank you! Tim "Dvdmandt" <[EMAIL PROTECTED]> wrote in message

[PHP] Re: Pipe $var to a shell command

2003-06-13 Thread DvDmanDT
Ok, last reply from me I think... Must read until I know for sure before I post... http://se.php.net/manual/en/function.proc-open.php seems to be just what you need! "Tim T" <[EMAIL PROTECTED]> skrev i meddelandet news:[EMAIL PROTECTED] > I have a mem var $myoutput I would like to pipe it to the i

[PHP] Re: Pipe $var to a shell command

2003-06-13 Thread DvDmanDT
Oh, sorry, I missunderstood you... You want $myoutput to be the programs input, not the output of the program... Hmm... Look into popen(), fputs() and fclose()... "Tim T" <[EMAIL PROTECTED]> skrev i meddelandet news:[EMAIL PROTECTED] > I have a mem var $myoutput I would like to pipe it to the input

[PHP] Re: Pipe $var to a shell command

2003-06-13 Thread Bobby Patel
maybe try exec? $instruction = "$myOutput > command "; # for piping (as I recall) I used to do the input from the right, but I don't think that will make a difference exec ($instruction); Bobby exec ("command "Tim T" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > I have a mem var $

[PHP] Re: Pipe $var to a shell command

2003-06-13 Thread DvDmanDT
Like $myoutput=`command`; ? "Tim T" <[EMAIL PROTECTED]> skrev i meddelandet news:[EMAIL PROTECTED] > I have a mem var $myoutput I would like to pipe it to the input of a > shell_exec command. > > I tried shell_exec("command < $myoutput") however this is not quite right. > Anybody have any ideas??