Re: [PHP] Re: PHP, over javascript code simple \n

2004-08-21 Thread Louie Miranda
single ' will work fine. :) not double " On Fri, 20 Aug 2004 11:49:10 +0200, aRZed <[EMAIL PROTECTED]> wrote: > > > > print(" > > if (document.rpcjs_louie.ColCustName.value == \"\") { walangfield += > > \"Missing: Firstname\n\"; } > > "); > > ?> > > try simply escaping the "\" before the "n" wi

[PHP] Re: PHP, over javascript code simple \n

2004-08-20 Thread aRZed
try simply escaping the "\" before the "n" with an additional "\" or in other words: use "\\n" instead of "\n". PHP will interpret "\\" as an "\". -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

[PHP] Re: PHP, over javascript code simple \n

2004-08-19 Thread Louie Miranda
Got it. use ' and not " because php reads if its under " On Fri, 20 Aug 2004 11:10:24 +0800, Louie Miranda <[EMAIL PROTECTED]> wrote: > Im having problems. Because my javascript is inside a PHP code. > Now below are 1 line code of a print function that display this on the > html header. > i must