Sajid --
...and then Sajid said...
%
% Hi,
Hi!
% Thanks for your help.
% But what i feel is that this is a more tedious process to achieve what i
% want to.
Sometimes database work is :-)
% What will happen in this is that i have to enter proper Continent ID and
% Country ID in both Country
My background is only with MS Access where everything is drag & drop. In
that case you can link fields and they will populate automatically. If
you have Access, it might be an easier way to set up the database, enter
the data and then export it to MySQL or whatever.
Sajid wrote:
I am not aware
I am not aware of linked tables too much, is this what is called linked
table?
Do i have to enter values on both tables to link them? Or can some columns
of one table be linked with columns of another table in some other way?
If no, then thanks for all who helped me :)
--sajid
"Adam Bregenzer"
On Tue, 2004-02-10 at 09:49, Sajid wrote:
> > A way you could do this, is to set up the tables like this:
> >
> > DG1:
> > Continent_Id | Continent_Name | Continent_Image | Continent_Text
> >
> > DG2: Country_Id | Continent_Id | Country_Name | Country_Image |
> Country_Text
> >
> > DG3: Club_Id | C
Hi,
Thanks for your help.
But what i feel is that this is a more tedious process to achieve what i
want to.
What will happen in this is that i have to enter proper Continent ID and
Country ID in both Country and Club tables respectively.
For that i have to go and check that these ID's are in the ot
"Sajid" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> HI,
>
> I have a problem.
>
> I dont know how to create tables for this in PHPMYADMIN, the situation is
> like this:
>
> I have to display lot of items on the screen.
>
> There are three Datagrids on the screen (I am using Flash
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