select distinct user.userId, fu.UserID as FriendID, fu.Name as FriendName
from user, friendlist as f, user as fu
where f.userkey = user.userkey and f.friendkey = fu.userkey
order by user.userId, friendId;
"Chris W" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> I sent this to
Probably something like this...
$str = "[hi] there, this is me [HI][HI] there, this is me";
$newstring = ereg_replace("(\[[A-Z]*][^]])", "\\1", $str);
I'm not sure if the "[^]]" should be "[^\]]" or not, but that might work.
If it doesn't you could always do:
$str = "[hi] there, this is me [HI]
In <[EMAIL PROTECTED]>, Chris Boget
wrote:
Either of these should work:
$str = preg_replace("/(\[[A-Z]+\])/","\\1",$str);
$str = ereg_replace("(\[[A-Z]+\])","\\1",$str);
e.g.:
\\1",$str);
//$str = ereg_replace("(\[[A-Z]+\])","\\1",$str);
print("$str");
?>
Jeff Warrington
> I've got the fo
> This is untested, but something like...
> $str = "[hi] there, this is me [HI] there, this is me";
> $newstring = ereg_replace("(\[[A-Z]*])", "\\1", $str);
> should do it.
> using the Perl regexe's might make it easier, but that should work.
That worked perfectly. Is there any way I can make it
This is untested, but something like...
$str = "[hi] there, this is me [HI] there, this is me";
$newstring = ereg_replace("(\[[A-Z]*])", "\\1", $str);
should do it.
using the Perl regexe's might make it easier, but that should work.
On Thu, 13 Dec 2001, Boget, Chris wrote:
> I've got the fol
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