> echo "This doesn't work\n'; // Displays: This doesn't work\n
Seems to me like that would generate parse error.. :s But yea, we get your
point.. :)
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\n must be included in double-quotes because it's treated like a variable.
echo "This works\n"; // Displays: This works
echo "This doesn't work\n'; // Displays: This doesn't work\n
> From: [EMAIL PROTECTED] (Labunski)
> Newsgroups: php.general
> Date: Mon, 5 Apr 2004 00:58:35 +0300
>
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