* Thus wrote Amon ([EMAIL PROTECTED]):
>
> Curt Zirzow thanks for your reply also. But that has nothing to do with
> reference. If you use reference or not.. it still would not result in an
> error (hee... I want an error :P)
function foo($v) {}
foo($asdf['qwer']);
PHP Notice: Undefined variable
Thanks for help Daniel Clark. I know i must use isset function but that was
not the issue. But thanks anyway:)
Curt Zirzow thanks for your reply also. But that has nothing to do with
reference. If you use reference or not.. it still would not result in an
error (hee... I want an error :P)
I guess
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