You need to do a join.
SELECT table1.ID AS PL_NAME, table1.ID AS PC_NAME, table1.ID AS PA_NAME FROM
table1, table2 WHERE (table2.PL = table1.ID) AND (table2.PC = table1.ID)
and (table2.PA = table1.ID) ;
Or something like that. Sorry I couldn't be of more help.
Respectfully,
Ligaya Turmelle
"T
Try something like is:
select a.Name as PL_Name,b.Name as PC_Name,c.Name as PA_Name from
(select * from table1,table2 where table1.ID=table2.PL) a,
(select * from table1,table2 where table1.ID=table2.PC) b,
(select * from table1,table2 where table1.ID=table2.PA) c
where a.description=b.description
Thank you to Rich who saved me from going nuts.
Have now got my members registration and login working.
Also thank you to Janet and Ed who kindly offered to help.
I would like to build an admin area allowing users to upload course work
when completed, so don't think you have heard the last from me
Keep in mind that we do not officially support Apache2 yet. Will be a
while before it will be anywhere near stable.
-Rasmus
On Sat, 5 Oct 2002, kramer wrote:
> Ok guys,
> To correcte all the typos, this is what I did.
> 1. Removed PHP( directory ) completely.
> 2. Start Apache - went fine( wit
Ok guys,
To correcte all the typos, this is what I did.
1. Removed PHP( directory ) completely.
2. Start Apache - went fine( without any reference of PHP )
3. Installed PHP in a simple directory( not Program Files et al. ), so now
its e:\php-4.2.3-Win32\...
4. Copied php4ts.dll to \WINNT\system32
Thanks Erwin. Unfortunately it doesn't work, even after I copied php4ts.dll.
How would I specify the drive:\Program Files, which has a space in-between.
Should I include single or double quote ?
I tried all these combinations...
LoadModule php4_module F:/Progra~1/php-4.2.3-Win32/php4ts.dll
Load
Kramer wrote:
> hi,
>
> I've Apache 2 running fine in my Windows 2000 machine. I installed PHP
> 4.2.3( from the zip-file method ).
> I copied php4apache.dll and php4apache2.dll to /WINNT/system32 and
> /WINNT as well( to be safe ).
>
> In my httpd.conf, either of the following startments are caus
Well, $_POST['userName'] is now working, but I could have sworn I was trying
that last night and it was returning the same error. Oh well, thanks for the
help guys.
"Chris Nielsen" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I have a simple form:
>
>
> E
> echo $HTTP_SERVER_VARS['userName'];
> ?>
Make it $_POST['userName'] (or $HTTP_POST_VARS['userName'], but that's
deprecated).
Jome
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