RE: [PHP] Please, Help dynamicaly creating an Array

2002-09-18 Thread Max Sullivan
x27;THREE'"; $b = "3"; $data1 = array('ONE'=>1,'TWO'=>2); $data2[$a] = $b; $test = $data1 + $data2; -Original Message- From: Marek Kilimajer [mailto:[EMAIL PROTECTED]] Sent: Wednesday, September 18, 2002 1:54 AM To: PHP Subject: Re: [PHP] Plea

Re: [PHP] Please, Help dynamicaly creating an Array

2002-09-18 Thread Marek Kilimajer
Try eval(), like this: $str= "'THREE'=>3, 'FOUR'=>4"; eval("\$data2 = array('ONE'=>1,'TWO'=>2,$str);"); Max Sullivan wrote: >I am trying to populate array values and keys from a variable with no >luck. > >Lets say I have the following array. > >$data1 = array('ONE'=>1,'TWO'=>2,'THREE'=>3,'FOU

[PHP] Please, Help dynamicaly creating an Array

2002-09-17 Thread Max Sullivan
I am trying to populate array values and keys from a variable with no luck. Lets say I have the following array. $data1 = array('ONE'=>1,'TWO'=>2,'THREE'=>3,'FOUR'=>4); And I want to create part of the array with the string below: $str= "'THREE'=>3, 'FOUR'=>4"; $data2 = array('ONE'=>1,'TWO'=